Assignment title: Information


1 HW#7 Power System Economics and Deregulation (Please send email to Wail Rashed for any questions ([email protected])) Due date Thursday March 30, 2017 (9:00 am / Chicago time) I will send you copy of the (Books pdf and Lecture note) to make it easier for your expert to solve below Questions.2 Problem 1: (10 points) The following problems are based on the following system. For each problem, determine whether the given dispatch is optimal or not. The fuel cost functions for the three units are 2 F1(P 1)  749.55  7P 1  0.002P 1 2 F2(P2)  1285  8P2  0.001P2 2 F3(P3)  1531 6P3  0.002P3 The minimum and maximum capacities of the three units are Unit No. Pi,min (MW) Pi,max (MW) 1 320 800 2 300 1200 3 275 1100 (1) If the load is 1300, the dispatch is P 1  387.5 , P2  275, and P3  637.5 . A. Yes, the dispatch is optimal. B. No, the dispatch is not optimal. (2) If the load is 2500, the dispatch is P 1  687.5 , P2  875 , and P3  937.5 . A. Yes, the dispatch is optimal. B. No, the dispatch is not optimal. (3) If the load is 3000, the dispatch is P 1  812.5 , P2  1125 , and P3  1062.5 . A. Yes, the dispatch is optimal. B. No, the dispatch is not optimal. (4) If the load is 1200, the dispatch is P 1  362.5 , P2  300 , and P3  612.5 . A. Yes, the dispatch is optimal. B. No, the dispatch is not optimal. Problem 2: (10 points) (1) In your own word, describe  What is restructuring, and  Why have some power systems been restructured? (2) What are the benefits of interconnected systems? (3) Name Six Independent System Operators (ISOs) operated in the US (Full Name).3 Problem 3: (10 points) Four areas are interconnected. The following table shows the generation and cost at each area when each area independently supplies its own load and when the four areas are centrally dispatched by a pool control center. Assume a split-savings pool agreement such that each area exporting receives its increased costs of production plus its proportionate share of 50% of the pool savings. Calculate (1) the price of pool energy and (2) the net operation cost for Area 1. Area Load Local Generatio n Supply Load Cost Pool Generatio n Supply Load Cost No MW MW $/h MW $/h 1 550 550 2,640 430 1,969 2 450 450 2,056 466 2,132 3 400 400 1,800 326 1,385 4 350 350 1,637 528 2,507 Total 1750 1750 8,134 1750 7,994 Problem 4: (20 points) In the following two problems, in case that multiple solutions exist,  Choose the solution that maximizes the traded volume, or  If many price levels give equal traded volume, choose the price of the mid-point. (1) Assume the following bidding information. Demand Price Demand Volume 104 5000 105.5 6000 106 12000 Supply Price Supply Volume 105 12000 106 6000 107 6000 Determine the market clearing price (MCP), market clearing quantity (MCQ), Social Welfare, Consumer Surplus, and Producer Surplus. (2) Assume the following bidding information. Demand Price Demand Volume 104 2000 105 2000 106 500 Supply Price Supply Volume 104.5 2000 105 5000 Write down the LP formulation for clearing the bids.4 Problem 5: (10 points) The following DC SF based LP formulation is used to calculate LMPs for a 3-bus system shown in Figure 1. r l min max r l min max l min r max T T T L L L η , η P P P γ , γ f SF * (A * P B * L) μ SF * (A * P B * L) f μ e A * P B * L c * P b * L                 ( ) 0  s.t. min 1 2 G1: 400MW @ 10 $/MWh G3: 200 MW @ 20 $/MWh L3: 450MW 3 Flow limit: 100MW Figure 1 Determine the LMP at Bus 2. The LP implementation in MATLAB is as follows. % LMP calculation, DC PTDF based method (bus 1 is the reference bus) %x=[G1 G3 L3]' % matrix of PTDFs, ref bus = 1 SF=[0 -2/3 -1/3; 0 -1/3 -2/3; 0 1/3 -1/3]; % Bus-unit incidence matrix A=[ 1 0; 0 0; 0 1]; % Bus-load incidence matrix B=[ 0; 0; 1]; % Flow limits vector %[f12 f13 f23] flow_limits=[1000 1000 100]'; % unit vector e=[1 1 1]'; %the dimension is number of buses Aeq=[e'*A -e'*B]; beq=[0]; A1=[SF*A -SF*B; -SF*A SF*B]; b1=[flow_limits; flow_limits]; f=[10 20 0]'; lb=[0 0 450]'; ub=[400 200 450]'; [x,fval,exitflag,output,lambda]=linprog(f,A1,b1,Aeq, beq,lb,ub); x lambda.eqlin lambda.ineqlin The solutions from LP is x = 300.0000 150.0000 450.0000 lambda.eqlin = -10.0000 lambda.ineqlin = 0.0000 0.0000 30.0000 0.0000 0.0000 0.00005 Problem 6: (20 points) The following DC SF based LP formulation is used to calculate LMPs for a 3-bus system, shown in Figure 2, with consideration of losses. Losses are always balanced at Bus 3. r l min max r l min max l max r max T T T T L L L η , η P P P γ , γ SF * A * P B * L D * f μ SF * A * P B * L D * f μ LF * A * P B * L e * A * P B * L c * P b * L                        ( ) ( ) ( ) ( ) s.t. min Loss Loss offset Loss Loss   1 2 G1: 400MW @ 10 $/MWh G2: 200 MW @ 20 $/MWh L3: 450MW 3 Flow limit: 255MW Figure 2 If we choose Bus 2 as the reference bus, the LMPs at the three buses are Bus No LMP ($/MWh) 1 10 2 20 3 31.7308 Determine the energy components, loss components, congestion components, and LMPs at all buses if we choose Bus 1 as the reference bus. If we choose Bus 1 as the reference bus, the LP implementation in MATLAB is as follows. % LMP calculation, DC PTDF based method with consideration of losses %x=[G1 G2 L3 Loss]' % Loss distribution factors D = [0 0 1]'; % Loss factors LF=[0 -0.02 -0.1]'; offset=-25; % Shifting factors SF=[0 -2/3 -1/3; 0 -1/3 -2/3; 0 1/3 -1/3]; % Bus-unit incidence matrix A=[ 1 0; 0 1; 0 0]; % Bus-load incidence matrix B=[ 0; 0; 1]; % Flow limits vector %[f12 f13 f23] flow_limits=[1000 255 1000]'; % unit vector e=[1 1 1]'; %the dimension is number of buses Aeq=[ e'*A -e'*B -1; LF'*A -LF'*B -1]; beq=[ 0; -offset]; A1=[ SF*A -SF*B -SF*D; -SF*A SF*B SF*D]; b1=[ flow_limits; flow_limits]; f=[10 20 0 0]'; lb=[0 0 450 -inf]'; ub=[300 200 450 inf]'; [x,fval,exitflag,output,lambda]=linprog(f,A1,b1,Aeq,be q,lb,ub); x lambda.eqlin lambda.ineqlin The solutions from LP is x = 298.3654 168.2692 450.0000 16.6346 lambda.eqlin = -10.0000 28.8462 lambda.ineqlin = 0.0000 28.2692 0.0000 0.0000 0.0000 0.00006 Problem 7: (20 points) Write down the LP formulation for calculating LMP for the following system with consideration of losses. Assume that system losses are balanced at Bus 2 (25%) and Bus 3 (75%). Network Data Line Index From Bus To Bus Resistance (p.u.) Reactance (p.u.) Flow Limit (MW) 1 1 2 0.002 0.01 1000 2 2 3 0.002 0.01 250 3 1 3 0.002 0.01 1000 Generation Bid Data Unit No Bus No MW Price ($/MWh) 1 1 200 14 2 1 300 15 3 2 300 30 Load Bid Data Load No Bus No MW Price ($/MWh) 1 2 150 40 2 3 450 40       3 0 2 3 1 3 0 1 3 1 3 0 1 3 2 SF     0.078 0 0.028 LF , Offset=-20 Problem 8: Extra (20 points) The following DC SF based LP formulation can be used to calculate LMPs. r l min max r l min max r l min max T T T f f f μ ,μ L L L η ,η P P P γ , γ f SF* (A * P B * L) μ e A * P B * L c * P b * L                 ( ) 0  s.t. min Determine the formula for LMP and prove the revenue adequacy of the LMP-based market.